FunSteak
Well-known member
Our rig is a 2017 Minnie Winnie 26A.
I'm preparing to replace our current lead acid house batteries with lithium. I'm looking for a bit of guidance on understanding the current state, and installing a DC-DC charger, so as not to burn up my alternator. If needed, I'm okay with disabling the boost switch on the dash and will carry a jump pack instead.
Goal is to disconnect charging direct from the alternator and add the DC-DC charger, while not disturbing shore power and generator charging.
The attached photo is what I have now. I'm unfortunately not near the rig at the moment, so am working from photos and the Winnebago wiring diagrams (a bit limited in details). I'd like to better understand a few things.
I believe the heavy red wire on the right with the green sleeve, coming from the salesman switch, goes to the generator starter. The one with the yellow sleeve, right side of the solenoid, goes to house batts. Full red one on left side of solenoid goes to chassis batt.
Is the smaller yellow wire, on the center lug of the solenoid, coming from the boost switch? I assume that when this is energized, the solenoid connects house to chassis for boosting. Disconnecting this should disable the solenoid, yes? Follow up to that - where does charging current from the alternator enter the system? That's what I think I really need to disable, in favor of the DC-DC charger.
Next, Would the output of the DC-DC charger go on the right-hard Solenoid connection?
Where does charge current from the converter/charger enter? Is it the small yellow wire on the right side of the solenoid? Or maybe one of the ones entering the salesman switch? Winnebago's drawing is helpful, but not at all complete.
I feel like I'm just missing a couple of details here. Thanks for any guidance.
PS: I will also replace the charger board in my converter/charger to one with a lithium charge profile. It's a WFCO WF-8955PEC. I believe there is a direct, slide in replacement charging board for it.
I'm preparing to replace our current lead acid house batteries with lithium. I'm looking for a bit of guidance on understanding the current state, and installing a DC-DC charger, so as not to burn up my alternator. If needed, I'm okay with disabling the boost switch on the dash and will carry a jump pack instead.
Goal is to disconnect charging direct from the alternator and add the DC-DC charger, while not disturbing shore power and generator charging.
The attached photo is what I have now. I'm unfortunately not near the rig at the moment, so am working from photos and the Winnebago wiring diagrams (a bit limited in details). I'd like to better understand a few things.
I believe the heavy red wire on the right with the green sleeve, coming from the salesman switch, goes to the generator starter. The one with the yellow sleeve, right side of the solenoid, goes to house batts. Full red one on left side of solenoid goes to chassis batt.
Is the smaller yellow wire, on the center lug of the solenoid, coming from the boost switch? I assume that when this is energized, the solenoid connects house to chassis for boosting. Disconnecting this should disable the solenoid, yes? Follow up to that - where does charging current from the alternator enter the system? That's what I think I really need to disable, in favor of the DC-DC charger.
Next, Would the output of the DC-DC charger go on the right-hard Solenoid connection?
Where does charge current from the converter/charger enter? Is it the small yellow wire on the right side of the solenoid? Or maybe one of the ones entering the salesman switch? Winnebago's drawing is helpful, but not at all complete.
I feel like I'm just missing a couple of details here. Thanks for any guidance.
PS: I will also replace the charger board in my converter/charger to one with a lithium charge profile. It's a WFCO WF-8955PEC. I believe there is a direct, slide in replacement charging board for it.