John,
Just to set the record straight, every physics and chemistry calculation is assumed to be at "standard presure" and "standard temperature" unless otherwise stated.
Standard temperature is defined as zero degrees Celsius (0 0C), which translates to 32 degrees Fahrenheit (32 0F) or 273.15 degrees kelvin (273.15 0K). This is essentially the freezing point of pure water at sea level, in air at standard pressure.
Standard pressure supports 760 millimeters in a mercurial barometer (760 mmHg). This is about 29.921 inches of mercury, and represents approximately 14.7 pounds per inch (14.7 lb/in2). Imagine a column of air measuring one inch square, extending straight up into space beyond the atmosphere. The air in such a column would weigh about 14.7 pounds. This is measured from sea level, which is more or less the same throughout the world (ignoring tides, major storms, etc.)
Here is a brief table of boiling point vs. altitude:
0' - 212
2k' - 208.4
4k' - 204.8
6k' - 201.1
8k' - 197.4
10k' - 193.6
12k' - 189.8
Though the fairly minor (in terms of psi) flucuations in atmospheric pressure won't make much difference in the boiling point of water (Few degrees) if you remove the pressure of the air against the radiator cap's releif valve then the ONLY pressure acting on the water would be the cap, in the case of a 14lb cap that would leave you with the equivlent of an open container.
As you can clearly see from the above examples, altitude makes a significant difference on the boiling point, and are taken directly from the American Society of Heating, Refrigerating and Air-Conditioning Engineers, Inc. 1997. ASHRAE Handbook - Fundamentals, Inch-Pound Edition. ASHRAE. Atlanta, GA. and can be calculated using the following formulae:
pressure (in. Hg) = 29.921* (1-6.8753*0.000001 * altitude, ft.)^5.2559
boiling point = 49.161 * Ln (in. Hg) + 44.932
I would be happy to explain them to you, if necesary.